x2) = (x31, x2) x1 x2 y -1.5 -2.0 +1 -1.0 0.0 +1 -0.5 1.0 +1 0.0 2.0 +1 0.5 1.0 +1 1.0 2.0 +1 1.5 3.75 +1 -1.0 -2.0 -1 -0.5 -1.0 -1 0.0 -3.0 -1 0.5 -0.5 -1 1.0 -2.0 -1 1.5 1.5 -1 Aufgabe 6.4 (2 Punkte) [...] von Datenpunkten (vgl. Abbildung 1): D = { (1, 3,−1), (2, 5,−1), (3, 6,−1), (4, 4,−1), (5, 2,−1), (6, 3,−1), (8, 4,−1), (9, 4,−1), (7, 3,−1), (5, 5,−1), (6, 9,+1), (11, 6,+1), (3, 9,+1), (4, 8,+1), (6, 8 [...] http://www-ai.cs.uni-dortmund.de/LEHRE/VORLESUNGEN/KDD/SS13/DATA/svm-data.csv -5 -4 -3 -2 -1 0 1 2 3 4 5 -5 -4 -3 -2 -1 0 1 2 3 4 5 Abbildung 2: Datenpunkte im R2 1. Beschreiben Sie, wie Sie die gegebenen Daten …

Columnwise Mining – Lecture Notes

B C D 3 C E 4 A C D 5 A B C D 6 A E 7 A B 8 A B C 9 A C D 10 B   →   A B C D E 1 1 2 2 1 4 2 3 4 3 5 5 4 5 6 6 7 8 9 7 8 9 8 10 9   →   A B C D E 1-1 1-2 2-4 2-2 1-1 4-9 5-5 8-9 4-5 3-3 7-8 9-9 6-6 10-10 [...] D E 2 A B E 3 A B D E 4 A B D 5 B C D E 6 B D E 7 A B C E 8 C D 9 A B D 10 A B D Item TIDlist A 1 2 3 4 7 9 10 B 1 2 3 4 5 6 7 9 10 C 1 5 7 8 D 1 3 4 5 6 8 9 10 E 1 2 3 5 6 7 C is eliminated. Initial class: [...] 1 2 3 4 5 6 7 9 10 OK D 1 3 4 5 6 8 9 10 OK E 1 2 3 5 6 7 OK 1-Partition A: A B 1 2 3 4 7 9 10 OK A D 1 3 4 9 10 OK A E 1 2 3 7 X 2-Partition A B: A B D 1 3 4 9 10 OK 1-Partition B: B D 1 3 4 5 6 9 10 OK …

Columnwise Mining – Lecture Notes

B C D 3 C E 4 A C D 5 A B C D 6 A E 7 A B 8 A B C 9 A C D 10 B   →   A B C D E 1 1 2 2 1 4 2 3 4 3 5 5 4 5 6 6 7 8 9 7 8 9 8 10 9   →   A B C D E 1-1 1-2 2-4 2-2 1-1 4-9 5-5 8-9 4-5 3-3 7-8 9-9 6-6 10-10 [...] D E 2 A B E 3 A B D E 4 A B D 5 B C D E 6 B D E 7 A B C E 8 C D 9 A B D 10 A B D Item TIDlist A 1 2 3 4 7 9 10 B 1 2 3 4 5 6 7 9 10 C 1 5 7 8 D 1 3 4 5 6 8 9 10 E 1 2 3 5 6 7 C is eliminated. Initial class: [...] 1 2 3 4 5 6 7 9 10 OK D 1 3 4 5 6 8 9 10 OK E 1 2 3 5 6 7 OK 1-Partition A: A B 1 2 3 4 7 9 10 OK A D 1 3 4 9 10 OK A E 1 2 3 7 X 2-Partition A B: A B D 1 3 4 9 10 OK 1-Partition B: B D 1 3 4 5 6 9 10 OK …

abgegeben zu werden. x1 x2 y -1.5 -2.0 +1 -1.0 0.0 +1 -0.5 1.0 +1 0.0 2.0 +1 0.5 1.0 +1 1.0 2.0 +1 1.5 3.75 +1 -1.0 -2.0 -1 -0.5 -1.0 -1 0.0 -3.0 -1 0.5 -0.5 -1 1.0 -2.0 -1 1.5 1.5 -1 Aufgabe 6.4 (2 Punkte) [...] von Datenpunkten (vgl. Abbildung 1): D = { (1, 3,−1), (2, 5,−1), (3, 6,−1), (4, 4,−1), (5, 2,−1), (6, 3,−1), (8, 4,−1), (9, 4,−1), (7, 3,−1), (5, 5,−1), (6, 9, +1), (11, 6, +1), (3, 9, +1), (4, 8, +1), (6 [...] finden Sie unter http://kirmes.cs.uni-dortmund.de/wid2011/data/svm-daten.csv -5 -4 -3 -2 -1 0 1 2 3 4 5 -5 -4 -3 -2 -1 0 1 2 3 4 5 Abbildung 2: Datenpunkte im R2 (a) Beschreiben Sie, wie Sie die gegebenen …

cost to travel from city A to city B: c A B C D E A 0.0 3.0 2.5 6.7 4.0 B 3.0 0.0 1.1 6.5 5.1 C 2.5 1.1 0.0 5.5 4.0 D 6.7 6.5 5.5 0.0 3.2 E 4.0 5.1 4.0 3.2 0.0 Implement an (1+1)-EA that minimises the cost [...] Lecture website: https://tinyurl.com/CI-WS2015-16 Sheet 5, Block I 14 January 2016 Due date: 27 January 2016, 2pm Discussion: 28/29 January 2016 Exercise 5.1: Variation Operations (8 Points) (a) Assume x, y [...] x22 with (x1, x2) ∈ R2 fr(x1, x2) = x21 + x22 − 10(cos(2πx1) + cos(2πx2)) + 20 with (x1, x2) ∈ [−5, 5]2 Set up an experiment that tests the theorem from lecture 9, slide 27 for the functions fc, fe, fr defined …

Slide 1

Array (Beispiel) int main() { int i, b[5] = { 0 }, a[] = { 2, 4, 6, 8, 10 }; inkrement(5, a); for (i = 0; i < 5; i++) cout << a[i] << “ “; cout << endl; for (i = 0; i < 5; i++) cout << b[i] << “ “; cout << [...] fehleranfällig! Kapitel 5 G. Rudolph: Einführung in die Programmierung ▪ WS 2013/14 4 Funktion in der Mathematik: f: R → R f(x) = sin(x) y = f(0.5) führt zur ● Berechnung von sin(0.5), ● Rückgabe des Ergebnisses [...] Zuweisung des Ergebnisses an Variable z. Funktionen Kapitel 5 G. Rudolph: Einführung in die Programmierung ▪ WS 2013/14 5 int main() { double x = 0.5, y, z; y = sin(x); z = sin(0.2); std::cout << y << “ “ << …

Slide 1

Array (Beispiel) int main() { int i, b[5] = { 0 }, a[] = { 2, 4, 6, 8, 10 }; inkrement(5, a); for (i = 0; i < 5; i++) cout << a[i] << “ “; cout << endl; for (i = 0; i < 5; i++) cout << b[i] << “ “; cout << [...] fehleranfällig! Kapitel 5 G. Rudolph: Einführung in die Programmierung ▪ WS 2014/15 4 Funktion in der Mathematik: f: R → R f(x) = sin(x) y = f(0.5) führt zur ● Berechnung von sin(0.5), ● Rückgabe des Ergebnisses [...] Zuweisung des Ergebnisses an Variable z. Funktionen Kapitel 5 G. Rudolph: Einführung in die Programmierung ▪ WS 2014/15 5 int main() { double x = 0.5, y, z; y = sin(x); z = sin(0.2); std::cout << y << “ “ << …

space 1 2 3 4 5 6 7 8 red = {1, 2, 3, 4, 5, 7, 8} green = {1, 2, 7, 8} blue = {2, 3, 5, 6} orange = {1, 2, 3, 4, 7, 8} purple = {1, 2, 3, 4, 5, 6} pink = {1, 2, 3, 4, 5, 6, 7} X = {1, 2, 3, 4, 5, 6, 7, 8} [...] space 1 2 3 4 5 6 7 8 red = {1, 2, 3, 4, 5, 7, 8} green = {1, 2, 7, 8} blue = {2, 3, 5, 6} orange = {1, 2, 3, 4, 7, 8} purple = {1, 2, 3, 4, 5, 6} pink = {1, 2, 3, 4, 5, 6, 7} X = {1, 2, 3, 4, 5, 6, 7, 8} [...] ofRp 5. sample newR′ 6. returnR′ 1 red = {1, 2, 3, 4, 5, 7, 8} 1 green = {1, 2, 7, 8} 1 orange = {1, 2, 3, 4, 7, 8} 6 8 2 3 1 4 5 7 W (r) The algorithm 1 blue = {2, 3, 5, 6} 1 purple = {1, 2, 3, 4, 5, 6} …